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-15x^2+45x+60=0
a = -15; b = 45; c = +60;
Δ = b2-4ac
Δ = 452-4·(-15)·60
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5625}=75$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-75}{2*-15}=\frac{-120}{-30} =+4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+75}{2*-15}=\frac{30}{-30} =-1 $
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